Filters
Question type

Study Flashcards

Calculate the pH of the solution resulting from the addition of 10.0 mL of 0.10 M NaOH to 50.0 mL of 0.10 M HCN (Ka = 4.9 * 10-10) solution.


A) 5.15
B) 8.71
C) 5.85
D) 9.91
E) 13.0

F) B) and D)
G) All of the above

Correct Answer

verifed

verified

Which one of the following is a buffer solution?


A) 0.40 M HCN and 0.10 KCN
B) 0.20 M CH3COOH
C) 1.0 M HNO3 and 1.0 M NaNO3
D) 0.10 M KCN
E) 0.50 M HCl and 0.10 NaCl

F) D) and E)
G) C) and D)

Correct Answer

verifed

verified

To 1.00 L of a 0.100 M aqueous solution of the week base pyridine (C5H5N) is added 1.00 mL of 14.0 M NaOH. What fraction of the pyridine molecules in the resulting solution react with water to release hydroxide ions? [Kb(C5H5N) = 1.7 * 10-9]


A) 1.2 * 10-7
B) 4.1 * 10-5
C) 0.14
D) 2.4 * 10-10
E) 1.3 * 10-5

F) A) and B)
G) C) and D)

Correct Answer

verifed

verified

Write a net ionic equation for the reaction occurring when a small amount of sodium hydroxide solution is added to a buffer solution containing NH4Cl and NH3.

Correct Answer

verifed

verified

OH- + NH<...

View Answer

Calculate the pH at the equivalence point for the titration of 0.22 M HCN with 0.22 M NaOH. (Ka = 4.9 * 10-10 for HCN)

Correct Answer

verifed

verified

Calculate the pH of a buffer solution prepared by dissolving 0.20 mole of cyanic acid (HCNO) and 0.80 mole of sodium cyanate (NaCNO) in enough water to make 1.0 liter of solution. [Ka(HCNO) = 2.0 * 10-4]


A) 0.97
B) 3.10
C) 4.40
D) 3.70
E) 4.30

F) All of the above
G) B) and E)

Correct Answer

verifed

verified

You have 500.0 mL of a buffer solution containing 0.20 M acetic acid (CH3COOH) and 0.30 M sodium acetate (CH3COONa) . What will the pH of this solution be after the addition of 20.0 mL of 1.00 M NaOH solution? [Ka = 1.8 * 10-5]


A) 4.41
B) 4.74
C) 4.56
D) 4.92
E) 5.07

F) D) and E)
G) C) and D)

Correct Answer

verifed

verified

Calculate the percent ionization of formic acid in a 0.010 M HCOOH solution. (Ka = 1.7 *10-4)

Correct Answer

verifed

verified

The pH at the equivalence point of a titration may differ from 7.0 due to


A) the initial concentration of the standard solution.
B) the indicator used.
C) the self-ionization of H2O.
D) the initial pH of the unknown.
E) hydrolysis of the salt formed.

F) None of the above
G) A) and E)

Correct Answer

verifed

verified

The solubility product for barium sulfate is 1.1 * 10-10. Calculate the molar solubility of barium sulfate.


A) 5.5 * 10-11 mol/L
B) 1.1 * 10-5 mol/L
C) 2.1 * 10-5 mol/L
D) 1.1 * 10-10 mol/L
E) 2.2 * 10-10 mol/L

F) C) and D)
G) None of the above

Correct Answer

verifed

verified

The solubility of strontium carbonate is 0.0011 g/100 mL at 20ΒΊC. Calculate the Ksp value for this compound.


A) 7.5 * 10-5
B) 1.5 * 10-4
C) 5.6 * 10-9
D) 7.5 * 10-6
E) 1.5 * 10-3

F) None of the above
G) A) and B)

Correct Answer

verifed

verified

Calculate the pH of a buffer solution that contains 0.25 M benzoic acid (C6H5CO2H) and 0.15M sodium benzoate (C6H5COONa) . [Ka = 6.5 * 10-5 for benzoic acid]


A) 3.97
B) 4.83
C) 4.19
D) 3.40
E) 4.41

F) D) and E)
G) A) and E)

Correct Answer

verifed

verified

Write a net ionic equation for the reaction occurring when a small amount of sodium hydroxide is added to a NaNO2/HNO2 buffer.

Correct Answer

verifed

verified

OH- + HNO...

View Answer

Calculate the pH at the equivalence point for the titration of 0.20 M HCl with 0.20 M NH3 (Kb = 1.8 * 10-5) .


A) 2.87
B) 4.98
C) 5.12
D) 7.00
E) 11.12

F) A) and B)
G) B) and D)

Correct Answer

verifed

verified

Solid sodium iodide is slowly added to a solution that is 0.0050 M Pb2+ and 0.0050 M Ag+.[Ksp (PbI2)= 1.4 * 10-8; Ksp (AgI)= 8.3 * 10-17] What percent of Ag+ remains in solution at this point?

Correct Answer

verifed

verified

1.0 * 10

View Answer

Calculate the percent ionization of formic acid in a solution that is 0.010 M HCOOH and 0.050 M HCOONa.(Ka = 1.7 * 10-4)

Correct Answer

verifed

verified

Calculate the percent ionization of formic acid in a solution that is 0.010 M HCOOH and 0.005 M HCOONa and compare your answer to the percent ionization you would calculate if the sodium formate were not present. Explain the difference, if any.(Ka = 1.7 * 10-4)

Correct Answer

verifed

verified

3.4%; the addition of formate ...

View Answer

Find the concentration of calcium ions in a solution made by adding 3.50 g of calcium fluoride to 750.mL of 0.125 M NaF. [For CaF2, Ksp = 3.95 * 10-11.]


A) 3.16 * 10-10 M
B) 2.53 * 10-9 M
C) 4.29 * 10-4 M
D) 6.32 * 10-10 M
E) 2.15 * 10-4 M

F) B) and E)
G) C) and E)

Correct Answer

verifed

verified

A solution is prepared by mixing 500.mL of 0.10 M NaOCl and 500.mL of 0.20 M HOCl.What is the pH of this solution? [Ka(HOCl) = 3.2 * 10-8]


A) 4.10
B) 7.00
C) 7.19
D) 7.49
E) 7.80

F) B) and D)
G) None of the above

Correct Answer

verifed

verified

The solubility of lead(II) iodide is 0.064 g/100 mL at 20ΒΊC. What is the solubility product for lead(II) iodide?


A) 1.1 * 10-8
B) 3.9 * 10-6
C) 1.1 * 10-11
D) 2.7 * 10-12
E) 1.4 * 10-3

F) B) and E)
G) A) and E)

Correct Answer

verifed

verified

Showing 41 - 60 of 110

Related Exams

Show Answer